15t-1.86t^2-25=0

Solution for 15t-1.86t^2-25=0 equation:

15t-1.86t^2-25=0

a = -1.86; b = 15; c = -25;
Δ = b2-4ac
Δ = 152-4·(-1.86)·(-25)
Δ = 39
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{39}}{2*-1.86}=\frac{-15-\sqrt{39}}{-3.72}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{39}}{2*-1.86}=\frac{-15+\sqrt{39}}{-3.72}
$